X^2+64x-567=0

Solution for X^2+64x-567=0 equation:

X^2+64X-567=0

a = 1; b = 64; c = -567;
Δ = b2-4ac
Δ = 642-4·1·(-567)
Δ = 6364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6364}=\sqrt{4*1591}=\sqrt{4}*\sqrt{1591}=2\sqrt{1591}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-2\sqrt{1591}}{2*1}=\frac{-64-2\sqrt{1591}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+2\sqrt{1591}}{2*1}=\frac{-64+2\sqrt{1591}}{2}
$